3x^2+2x+3=59

Solution for 3x^2+2x+3=59 equation:

3x^2+2x+3=59

We move all terms to the left:

3x^2+2x+3-(59)=0

We add all the numbers together, and all the variables

3x^2+2x-56=0

a = 3; b = 2; c = -56;
Δ = b2-4ac
Δ = 22-4·3·(-56)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-26}{2*3}=\frac{-28}{6}
=-4+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+26}{2*3}=\frac{24}{6}
=4
$